Predicate Logic MCQs are very important test and often asked by various testing services and competitive exams around the world. Here you will find all the Important Predicate Logic MCQs for Preparation.
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Predicate Logic Online MCQs with Answers
Predicate logic extends propositional logic by introducing:
a) Variables
b) Connectives
c) Truth tables
d) Quantifiers
In predicate logic, a predicate is:
a) A statement that is always true.
b) A statement that is always false.
c) A function that maps variables to values.
d) A statement that depends on one or more variables.
The quantifiers used in predicate logic are:
a) ∃ (exists) and ∀ (for all)
b) ∨ (or) and ∧ (and)
c) ⊃ (implies) and ¬ (not)
d) ⊕ (exclusive or) and ↔ (if and only if)
The symbol ∃ is read as:
a) And
b) Not
c) There exists
d) For all
The symbol ∀ is read as:
a) And
b) Not
c) There exists
d) For all
The statement “There exists an x such that P(x)” can be symbolically represented as:
a) ∃x P(x)
b) ∃x ¬P(x)
c) ∀x P(x)
d) ∀x ¬P(x)
The statement “For all x, P(x)” can be symbolically represented as:
a) ∃x P(x)
b) ∃x ¬P(x)
c) ∀x P(x)
d) ∀x ¬P(x)
The statement “There exists an x such that ¬P(x)” can be symbolically represented as:
a) ∃x P(x)
b) ∃x ¬P(x)
c) ∀x P(x)
d) ∀x ¬P(x)
The statement “For all x, ¬P(x)” can be symbolically represented as:
a) ∃x P(x)
b) ∃x ¬P(x)
c) ∀x P(x)
d) ∀x ¬P(x)
The negation of the statement “∃x P(x)” is:
a) ∃x P(x)
b) ∃x ¬P(x)
c) ∀x P(x)
d) ∀x ¬P(x)
The negation of the statement “∀x P(x)” is:
a) ∃x P(x)
b) ∃x ¬P(x)
c) ∀x P(x)
d) ∀x ¬P(x)
The quantified statement “∀x (P(x) → Q(x))” can be read as:
a) For every x, P(x) or Q(x).
b) There exists an x such that P(x) implies Q(x).
c) For all x, if P(x) then Q(x).
d) There exists an x such that P(x) and Q(x).
The quantified statement “∃x (P(x) ∧ Q(x))” can be read as:
a) For every x, P(x) or Q(x).
b) There exists an x such that P(x) implies Q(x).
c) For all x, if P(x) then Q(x).
d) There exists an x such that P(x) and Q(x).
The quantified statement “∀x (P(x) ∨ Q(x))” can be read as:
a) For every x, P(x) or Q(x).
b) There exists an x such that P(x) implies Q(x).
c) For all x, if P(x) then Q(x).
d) There exists an x such that P(x) and Q(x).
The quantified statement “∃x (P(x) → Q(x))” can be rewritten as:
a) ∀x (P(x) ∨ Q(x))
b) ¬∀x (P(x) ∨ Q(x))
c) ∀x (P(x) → Q(x))
d) ¬∃x (P(x) ∨ Q(x))
The quantified statement “∀x (P(x) ∧ Q(x))” can be rewritten as:
a) ∃x (P(x) ∨ Q(x))
b) ¬∃x (P(x) ∨ Q(x))
c) ∃x (P(x) ∧ Q(x))
d) ¬∀x (P(x) ∨ Q(x))
The quantified statement “∀x (P(x) ∨ Q(x))” can be rewritten as:
a) ∃x (P(x) ∨ Q(x))
b) ¬∃x (P(x) ∨ Q(x))
c) ∃x (P(x) ∧ Q(x))
d) ¬∀x (P(x) ∨ Q(x))
The quantified statement “∃x (P(x) → Q(x))” can be rewritten as:
a) ∀x (P(x) ∨ Q(x))
b) ¬∀x (P(x) ∨ Q(x))
c) ∀x (P(x) → Q(x))
d) ¬∃x (P(x) ∨ Q(x))
The quantified statement “∃x (P(x) ∧ Q(x))” can be rewritten as:
a) ∀x (P(x) ∨ Q(x))
b) ¬∀x (P(x) ∨ Q(x))
c) ∀x (P(x) → Q(x))
d) ¬∃x (P(x) ∨ Q(x))
The quantified statement “∀x (P(x) ∧ Q(x))” can be rewritten as:
a) ∃x (P(x) ∨ Q(x))
b) ¬∃x (P(x) ∨ Q(x))
c) ∃x (P(x) ∧ Q(x))
d) ¬∀x (P(x) ∨ Q(x))
The negation of the statement “∀x (P(x) ∧ Q(x))” is:
a) ∃x (P(x) ∨ Q(x))
b) ¬∃x (P(x) ∨ Q(x))
c) ∀x (P(x) ∨ Q(x))
d) ¬∀x (P(x) ∨ Q(x))